A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?

Question

Jitender Pal · Answer

(b) AF = AB – BF = AB – DE = 50 – 20 = 30 m His displacement is AD AD = √(AF^2-DF^2 ) = √(〖30〗^2+〖40〗^2 ) = 50m In ∆AED tan θ = DE/AE = 30/40 = ¾ ⇒ θ = tan-1 (3/4) His displacement from his house to the field is 50 m, tan-1 (3/4) north to east.

Gaurav Kumar · Answer

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A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?

A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?

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A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?

A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?

2 Answers

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