A bus started from rest with a new acceleration 2 m/s^2.Show that, a man running with a velocity 10m/s^1 can never catch the bus if he is more than 25 metre behind it.

Question

Shivam Shekhar · Answer

Let the Separation between them be LVt=1/2at^2+LFrom values....10t+L=t^2For L being max dL/dt should be zero Hence by differentiation 2t=10t=5Hence L max=25

Shivam Shekhar · Answer

t=5 (after 2t=10)______________________________________________________________________________________________________________6_6__________________

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A bus started from rest with a new acceleration 2 m/s^2.Show that, a man running with a velocity 10m/s^1 can never catch the bus if he is more than 25 metre behind it.

A bus started from rest with a new acceleration 2 m/s^2.Show that, a man running with a velocity 10m/s^1 can never catch the bus if he is more than 25 metre behind it.

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A bus started from rest with a new acceleration 2 m/s^2.Show that, a man running with a velocity 10m/s^1 can never catch the bus if he is more than 25 metre behind it.

A bus started from rest with a new acceleration 2 m/s^2.Show that, a man running with a velocity 10m/s^1 can never catch the bus if he is more than 25 metre behind it.

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

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