0

Guest

Courses New

a body of mass 10 kg slides along a rough horizontal surface.the coefficient of friction is 1/root3 .the least force which acts at an angle of 30 0 to the horizontal

a body of mass 10 kg slides along a rough horizontal surface.the coefficient of friction is 1/root3 .the least force which acts at an angle of 300 to the horizontal

Grade:8

1 Answers

Vikas TU
14149 Points
6 years ago
The least force required here for the coefficient of friction 1/root(3) is:
        
F = mgsinѲ/µ
                     = (10x5x√3)/ (1/√3)
                     = 150 N

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More