A ball is thrown at an angle 0 ( this is thita) other is thrown at angle (90-0) .with horizontal direction from the same point each with speed of 40ms-1 .The second ball reaches 50m higher than the first ball. find their individual heights.

Question

Nitin · Answer

Difference of heights: u 2 /2g* cos2x equals 50 cos2x is 5/8 cos 2 x is 13/16 sin 2 x is 3/16 Height of theeta is 65m [16*5] Height of 90-theeta is 15m[3*5]

Parul Rajput · Answer

What have you done after finding cos2x..i am not getting the solution.. Please solve it briefly.and how the value of cos^2 x and sin ^2x come.

Nitin · Answer

here U go . By the way Briefly means in short. The formula of height is in sin 2 x so one becomes sin 2 x other become cos 2 x difference is in form cos 2 x-sin 2 x which is cos2x now the formula, 1+cos2x is 2cos 2 x 1-cos2x is 2sin 2 x plug in the value after that in formulas: HOPE IT HELPS:

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A ball is thrown at an angle 0 ( this is thita) other is thrown at angle (90-0) .with horizontal direction from the same point each with speed of 40ms-1 .The second ball reaches 50m higher than the first ball. find their individual heights.

A ball is thrown at an angle 0 ( this is thita) other is thrown at angle (90-0) .with horizontal direction from the same point each with speed of 40ms-1 .The second ball reaches 50m higher than the first ball. find their individual heights.

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A ball is thrown at an angle 0 ( this is thita) other is thrown at angle (90-0) .with horizontal direction from the same point each with speed of 40ms-1 .The second ball reaches 50m higher than the first ball. find their individual heights.

A ball is thrown at an angle 0 ( this is thita) other is thrown at angle (90-0) .with horizontal direction from the same point each with speed of 40ms-1 .The second ball reaches 50m higher than the first ball. find their individual heights.

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