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vindhya Grade: 12
        
a ball is projected with a speed u at an angle theta to the horizontal. the range R of the projectile is given by 
R=u^2 sin2theta/g
for which value of theta the range will be maximumfor a given speed of projectile.
(g is constant)
one year ago

Answers : (6)

vindhya
50 Points
										
please help. its very urgent
one year ago
erra akhil
208 Points
										
For 45degrees the range is maximum
 
one year ago
erra akhil
208 Points
										
Dear Vindhya,
u2sin2θ/g=Range-----eq.1
since maximum value of sinθ=1 and it is possible only when θ=90
here in eq.1,
for sin2θ to  be maximum, 2θ=90;
which implies θ=45 in this case.
Hence range is maximum when theta is 45degrees 
one year ago
erra akhil
208 Points
										
Approve my answer helped you.
 
one year ago
vindhya
50 Points
										
thanks but options are given as-
  1. pi/2 radian
  2. pi/3 radian
  3. pi/4 radian
  4. pi/6 radian
  5.  
one year ago
vindhya
50 Points
										
so, is the answer pi/4 radian ?
one year ago
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