A 20 Kg block is initially at rest. A 70 N force is required to set the block in motion. after the motion 60N is applied to keep block moving with constant speed.the coefficient of statistic friction.

Question

Vikas TU · Answer

Writing the balanced equation fo the block as: f = uN = 70 (least condition) 200*u = 70 u = 70/200=> 7/20

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A 20 Kg block is initially at rest. A 70 N force is required to set the block in motion. after the motion 60N is applied to keep block moving with constant speed.the coefficient of statistic friction.

A 20 Kg block is initially at rest. A 70 N force is required to set the block in motion. after the motion 60N is applied to keep block moving with constant speed.the coefficient of statistic friction.

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A 20 Kg block is initially at rest. A 70 N force is required to set the block in motion. after the motion 60N is applied to keep block moving with constant speed.the coefficient of statistic friction.

A 20 Kg block is initially at rest. A 70 N force is required to set the block in motion. after the motion 60N is applied to keep block moving with constant speed.the coefficient of statistic friction.

1 Answers

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