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If any object is travelling at a constant acceleration i.e. 5m/s/s then the distance covered by that object after 4s as per the formula S=ut+0.5att is 40m but if I calculate the same through v=u+at the same is coming to 50m. Will apprecite if you can explain where my understanding is wrong.

If any object is travelling at a constant acceleration i.e. 5m/s/s then the distance covered by that object after 4s as per the formula S=ut+0.5att is 40m but if I calculate the same through v=u+at the same is coming to 50m.


Will apprecite if you can explain where my understanding is wrong.

Grade:12

1 Answers

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
14 years ago

Dear Swarnendu Sengupta,

Ans:- I think you want a long walk in fresh air. It would refresh your mind and you will not do silly mistakes again.

S=0.5×5×4²=40 m   OK

Then v=0+(5×4)=20m/s

Let the ditance travelled by it is=X

v²=u²+2fX

20²=0+(2×5)X

X=40m

Hence X=S UNDERSTOOD ?

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All the best Swarnendu Sengupta !!!

 


Regards,

Askiitians Experts
Soumyajit Das IIT Kharagpur

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