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niharika pk Grade: 11
        

a non-uniform rod AB has a mass M and length 2l.The mass per unit lengthof the rod is mx at a point of the rod distant x from A. find the moment of inertia of this rod about an axis, a)through A,


b) through the mid point of AB.

7 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear niharika


let a element of length dx at adistance x from the point A of the rod.


mass of this element will be dm = mxdx


so moment of inertia of this element about point A is


  dI = dm * x2


for moment of inertia of whole rod perform intigration


I=  ∫dI = o2Ldm * x2


            =o2Lm * x3 dx


            =4mL4


and we know M =o2Ldm


                      = o2Lmxdx


                      =2mL2


so moment of inerta  I =2ML2


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7 years ago
Arijit Banerjee
18 Points
										

1.  Particles of masses 1g,2g,3g,....,100g are kept at the marks 1cm,2cm,3cm,...,100cm respectively on a metre scale .Find the moment of inertia of the system of particles about a perpendicular bisector of the metre scale.


 2.  

4 years ago
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