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neeru . Grade: 11
`        what is reduced mass?plz...explain with an example,where  it is used  and what are the conditions?`
7 years ago

147 Points
```										Dear neru
The reduced mass m (kg) of a system of two bodies is determined as
1/μ  = 1/ma   + 1/mb
where ma and mb are the masses (kg) of the bodies.

Suppose you have 2 objects with masses M  and m that exert a force on each other as shown.

So  mass, force & acceleration

Quantity
Mass M
mass m

Mass
M
m

Force
-F
F

Acceleration
aM = -F/M
am = F/m

Newton's laws of action/reaction have  been used.  Calculating quantities such  as distances between them looks complex, but there is a nifty tool.  View  the system in the reference frame of one of the objects (say mass M).
Now mass M is stationary, but mass m  is still free to move under the force F, with one catch.  When one views a situation in the frame of an object with acceleration a, all  objects have as there acceleration the acceleration due to the forces on it minus  this acceleration a.  For the case of mass m

am´ = F/m - aM = F·(1/m + 1/M) = F/(m·M/(m + M))

In other words, mass m behaves as if  it instead has a mass μ = m·M/(m + M).  This is called the reduced mass.
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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