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one second after projection a stone moves at an angke of 45degree with the horizantal.two seconds after projectioin it moves horizantly . its angel of projection in degree is ???
Dear jauneet
let angel of projection is Θ and initial velocity is U
so verticle velocy = UsinΘ
horixontal velocity =UcosΘ
after 1 sec verticle velocity will be
V = UsinΘ -g
horizontal velocity will remain same
so tan45 =1 = [UsinΘ -g]/UcosΘ .............1
after 2 sec verticle velocity will be zero
0 = UsinΘ -2g
g = UsinΘ /2
put this value in equation 1
1 = [UsinΘ -UsinΘ /2 ]/UcosΘ
1 = tanΘ /2
tanΘ =2
Θ =tan-12
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