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one second after projection a stone moves at an angke of 45degree with the horizantal.two seconds after projectioin it moves horizantly . its angel of projection in degree is ???

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7 years ago

147 Points
```										Dear jauneet
let angel of projection is Θ and initial velocity is U
so verticle velocy = UsinΘ
horixontal velocity =UcosΘ
after 1 sec verticle velocity will be
V = UsinΘ -g
horizontal velocity will remain same
so tan45 =1 = [UsinΘ -g]/UcosΘ   .............1
after 2 sec verticle velocity will be zero
0 = UsinΘ -2g
g = UsinΘ /2
put this value in equation 1
1 = [UsinΘ -UsinΘ /2 ]/UcosΘ
1 = tanΘ /2
tanΘ =2
Θ =tan-12
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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