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The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be:


a) ut+(1/3)bt2


b) ut+(1/2)bt2


c) ut+(1/6)bt3


d) ut+(1/3)bt3


 

6 years ago

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Answers : (1)

										

Dear abhingya


d2s/dt2 =bt


intigrate


V= ds/dt = bt2/2 +c


at t=0 V=U


so U =0 +c


ds/dt = bt2/2 +U


furthet intigrate


s= b/6 t3 +Ut +d


at t=0 s=0


so d=0


S =b/6 t3 +Ut


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