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The acceleration of a particle is increasing linearly with time t as bt. The particle starts from origin with initial velocity u. The distance travelled by the particle in time t will be:

a) ut+(1/3)bt2

b) ut+(1/2)bt2

c) ut+(1/6)bt3

d) ut+(1/3)bt3


6 years ago


Answers : (1)


Dear abhingya

d2s/dt2 =bt


V= ds/dt = bt2/2 +c

at t=0 V=U

so U =0 +c

ds/dt = bt2/2 +U

furthet intigrate

s= b/6 t3 +Ut +d

at t=0 s=0

so d=0

S =b/6 t3 +Ut

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6 years ago

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