Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Kinematics & Rotational Motion
  • View Details
Get extra R 150 off


An Electron Trapped in an Atom

7 years ago


Answers : (1)



Now we are ready to study an electron trapped in an atom. For simplicity, we choose the simplest atom—hydrogen--which contains only one electron. To define the problem we must identify the potential energy function for this electron, for a finite well. In that case the motion of the electron was on dimensional. The electron in the hydrogen atom, however, can move in three dimension. Its potential energy, conveniently, involves only a single variable—namely, the radial distance r from the nucleus to the electron.

The potential energy function follows from Coulomb’s law and is:-

In which +e is the charge of the central proton and –e is that of the electron. It too, is a potential well. In the figure we have expressed the radial separation as a dimensionless ratio r/a0. The constant a0 called the Bohr radius. Is a convenient unit of length for distances on the atomic scale. Its numerical value, as we discuss later in this section is 52.9 pm, which is approximately the radius of a typical atom.

In the next section we will begin to consider the solutions to Schrodinger’s equation for the hydrogen atom. First, however, we give a brief review of the historical background.

7 years ago

Post Your Answer

Other Related Questions on General Physics

a cricket ball is thrown at a speed of 28m/s in a direction 30*( 30 degrees) above the horizontal .Calculate its maximum height.
Here, velocity of projection, u = 28 m/s. Angle of projection, = 30 ০ . We have, maximum height attained by a projectile, So, the maximum height attained by the ball is 20 m. THANKS
Shaswata Biswas 29 days ago
It sould be, So, the maximum height attained by the cricket ball will be 10 . Sorry for mistake. THANKS
Shaswata Biswas 29 days ago
a wheel of perimeter 4 Pi m is rolling on a horizontal surface. The displacement of the point of contact of wheel and ground when the wheel completes one quarter of revolution is
See , the perimeter of wheel is 4 pi meter. So, each rotaion the wheel makes, it goes a distance 4 pi meter. So, the quarter of a revolution makes the displacement = (4 pi / 4) meter = pi...
KAPIL MANDAL one month ago
The density of waterr is max. at 40 C.please explain in physics terminology
Because at 4 degree celsium the temperature force is balanced from all the sides. H2O molecules have a lots of free space and thus above freezing point the water starts melting and with the ...
2017 years ago
In the isothermal expansion of 10g of gas from volume V to 2V the work done by the gas is 575J. What is the root mean square speed of the molecules of the gas at that temperature ?
In isothermal expansion work done is given as: W = nRTln(Vf/Vi) = nRTln(2v/v) = nRTln2 575 = nRTln2 T = 575/nRln2......................(1) Root Mean Square Method: Vrms =...
Vikas TU 2 months ago
Is there any book on theory of relative velocity of approach and separation
@ manju h c ver ma is the best one for that , it explains the relative velocity part in a little bit of detail by taking the example of diffrent scenario . so, u can use that , they also...
Umakant biswal 3 months ago
I think cengage physics mechanics-1 is the best because there is a complete explaination about all cases like minimum time of approach also angle of particles without using calculus and in...
benny bhai 3 months ago
DC Pandey explains the topic clearly andcan be very helpful to do problems related to relative velocity.So I would recommend you Mechanics-I by DC Pandey.
Mudit 3 months ago
Is there any formula which can help me to find out the stregth of magnetic field required to catch a very fast moving object of very negligiable mass around 0.32 gm.
When we can find the strength of magnetic field of a moving charge(a bunch of electrons of very quantum mass), then m = 0.32 gm is very massive as compare to the massof an electron or...
Saurabh Kumar 7 months ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,750 off

  • Kinematics & Rotational Motion
  • View Details

Get extra R 150 off

More Questions On General Physics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details