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```        A BALLOON IS ASCENDING WITH AN ACC. OF 0.2m/s^2. TWO STONES ARE DROPPED FROM IT AT AN INTERVAL OF 2s.FIND THE DISTANCE BETWEEN THEM 1.5s AFTER THE SECOND STONE IS RELEASED.
A)49m      B)48m       C)50m        D)47m```
7 years ago

147 Points
```										Dear vikas
let when first stone is drop speed of the baloon is u
so after 2 sec
h=2u + 1/2 * .2 * 4
=2u+.4
and after 2 sec apeed of the baloon
v=u+2*.2
=u+.4
let h1 distance travell by first stone in (2+1.5) sec after it was dropped
h1 =u(3.5 ) -1/2 *g *(3.5)2
let h2 distance travell by second stone in 1.5 sec
so  h2= (u+.4)*2 -1/2 *g*(1.5)2
so different between two stone =|h1-h2-h|
=50 m

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```
7 years ago
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