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A BALLOON IS ASCENDING WITH AN ACC. OF 0.2m/s^2. TWO STONES ARE DROPPED FROM IT AT AN INTERVAL OF 2s.FIND THE DISTANCE BETWEEN THEM 1.5s AFTER THE SECOND STONE IS RELEASED.                                                                             

A)49m      B)48m       C)50m        D)47m

6 years ago


Answers : (1)


Dear vikas

let when first stone is drop speed of the baloon is u

so after 2 sec

 h=2u + 1/2 * .2 * 4


 and after 2 sec apeed of the baloon



let h1 distance travell by first stone in (2+1.5) sec after it was dropped

 h1 =u(3.5 ) -1/2 *g *(3.5)2

let h2 distance travell by second stone in 1.5 sec

 so  h2= (u+.4)*2 -1/2 *g*(1.5)2

so different between two stone =|h1-h2-h|

                                             =50 m

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6 years ago

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