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A car accelerates from rest at constant rate of 2 m/sec/sec for some time. Then it retards at a constant at a constant rate of 4 m/sec/sec and comes to rest. What is the maximum speed attained by the car, if it remains in motion for 3 seconds?
options: (1) 2 m/sec (2) 3 m/sec (3) 4 m/sec (4) 6 m/sec
pls give explanation also...u may reply on my email ID... anurag_can@yahoo.com....also which is best textbook for Kinematics? thanks
I think the ans is 4m/sec...Draw V-t Graph properly and then u can solve
use the fact the slope of vt graph is acceleration and slope = tan theta = Perpendicular(here maximum velocity)/Base
Let Times be t1 and t2
acc. to graph ull get 2=P/t1 and 4=P/t2
or we can write 1/2 = t1/P and 1/4 = t2/P
adding both we will get t1 + t2/P or 3/p = 3/4 (t1 + t2 = 3)
SOLVE AND FIND p..
..I am too an iit aspirant +1 class..i THINK cS PANDEY HC VERMA ARE GOOD BUS TO START WITH..;)
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