MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Akash Sengupta Grade: 11
        A force F=(10i+5j)N acts on a body of mass 10gm.If the body is at origine at time t=0,then what would be its position at time t=5s?
7 years ago

Answers : (1)

Ramesh V
70 Points
										

F = 10i + 5j  


as F=ma where m=0.01kg


accl. of body(a) = 1000i+500j


equation of motion is : S = ut + 0.5at2 with starting at rest , u =0


position = (0.5*1000*25 i + 0.5*500*25 j )


            = (12500 i + 6250 j)


--


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult
to understand - post it here and we will get you the answer and detailed solution very quickly.We are all
IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Ramesh  
IIT Kgp - 05 batch




7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
  • Kinematics & Rotational Motion
  • OFFERED PRICE: R 600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details