In formula P = (nRT)/(v - b) e -a/RTV . Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.

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Ramesh V · Answer

P is pressure in N/m 2 dimensional formula is : ML -1 T -2 n is dimension less dimesnion of temperature represented by the Greek letter theta is q a/RTV shld be dimension less whihc means a has dimesnions same as RTV dimesnion of a is : ML 5 T -2 b has dimensions same as volume i.e, m 3 or L 3 so, dimesnion of a is : ML 5 T -2 dimesnion of b is : L 3 -- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch

soumy jain · Answer

In formula P = (nRT)/(v - b) e-a/RTV. Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.pls explain it step wise and at each sinle level

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In formula P = (nRT)/(v - b) e -a/RTV . Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.

In formula P = (nRT)/(v - b) e^-a/RTV. Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.

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In formula P = (nRT)/(v - b) e -a/RTV . Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.

In formula P = (nRT)/(v - b) e-a/RTV. Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.

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In formula P = (nRT)/(v - b) e^-a/RTV. Find dimensions of a and b where P = pressure, n = no. of moles, T = temperature, V = volume and R = Universal Gas constant.