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`        2 Litres of mercury at 80 degree celsius is pushed into a plastic bucket containing 10 litres of mercury at temprature T. If the final temperature of the mixture is 30 degree celsius. What is the value of T?`
6 years ago

105 Points
```										Dear vikas,
the heat lost by 80 degree mercury is taken by mercury at T degrees
using
M1Cp (80-30) = M2Cp (T-30)
density *volume *(50) = Density * volume (T-30)
2 *50 = 10 * (T-30)
=> 10 = T -30
=> T = 40 degrees
All the best.
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6 years ago
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