MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Amit Tapas Grade: 10
        

A particle is thrown  vertically upwards.Its velocity at one fourth of maximum height is 20m/s.Then the max height is

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

let H is maximum height ...


if initial velocity is u then


applying , v2 = u2 + 2as


at maximum height , v=0 , s=H , a=-g   ,after putting these


         0 = u2 -2gH     or  u2 = 2gH    ...................1


again applying , v2 = u2 + 2as upto that instant when its velocity was 20m/s...


   s = H/4 , v = 20m/s


           202 = u2 - 2g(H/4)         .........2


from 1 putting u2 in 2


        202 = 2gH - 2g(H/4)


       400 = 2gH/3


      H=80/3 = 26.7m


approve if u like my ans

6 years ago
Fawz Naim
37 Points
										

if the maximum height is H then at one-fourth of this height


v^2=u^2-2gH/4, v=20m/s


400+2gH/4=u^2 .....1


now at the heighest point v=0


v^2=u^2-2gH


0=u^2-2gH


u^2=2gH


putting value of u^2 from equation 1


400+2gH/4=2gH


H=80/3 m

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 13,000 off
USE CODE: JEE1
  • Kinematics & Rotational Motion
  • OFFERED PRICE: R 600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details