Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Amit Tapas Grade: 10
`        A particle is thrown  vertically upwards.Its velocity at one fourth of maximum height is 20m/s.Then the max height is`
6 years ago

## Answers : (2)

510 Points
```										let H is maximum height ...
if initial velocity is u then
applying , v2 = u2 + 2as
at maximum height , v=0 , s=H , a=-g   ,after putting these
0 = u2 -2gH     or  u2 = 2gH    ...................1
again applying , v2 = u2 + 2as upto that instant when its velocity was 20m/s...
s = H/4 , v = 20m/s
202 = u2 - 2g(H/4)         .........2
from 1 putting u2 in 2
202 = 2gH - 2g(H/4)
400 = 2gH/3
H=80/3 = 26.7m
approve if u like my ans
```
6 years ago
Fawz Naim
37 Points
```										if the maximum height is H then at one-fourth of this height
v^2=u^2-2gH/4, v=20m/s
400+2gH/4=u^2 .....1
now at the heighest point v=0
v^2=u^2-2gH
0=u^2-2gH
u^2=2gH
putting value of u^2 from equation 1
400+2gH/4=2gH
H=80/3 m
```
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on General Physics

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
• Kinematics & Rotational Motion
• OFFERED PRICE: Rs. 636
• View Details
Get extra Rs. 51 off
USE CODE: Neerajwin