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A stone is thrown with an initial speed of 4.9m/s from a bridge in vertically upward direction .It falls in ground in 2 sec.find height of bridge.Please explain with diagram
dear amit ,
u is given = 4.9 , total time of flight = 2sec
applying , S = ut + at2/2 ,
S = H = ? , a=-g , u=+4.9m/s (upward)
putting these in above eq
H = 4.9*2 - 9.8(4)/2 = 9.8m
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