Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Three identical uniform rods each of length 40cm and mass 2kg form an equilateral triangle. Find the moment of inertia of this system about an axis passing through one corner ?
Thanks in advance !
let ABC is the triangle formed by these rods then we have to find moment of inertia any about vertex , let vertex be A...
then , rod AB & AC will have same moment of inertia about end A ,
IAC = IAB = mL2/12 + mL2/4 = mL2/3
moment of inertia of BC = mL2/12 + md2 (d is perpendicular distance from axis of rotation)
from triangle ABC , d = Lcos30
IBC = mL2/12 + 3mL2/4 = 10mL2/12
net moment of inertia = IAB+IBC+IAC
Inet =18mL2/12 = 3mL2 /2
Inet = 0.48kg-m2
approve my ans if u like it
Thanks a Lot
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !