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Akhilesh Gandhi Grade: 11
        

a man of 85 kg lowers himself from 10 m height  holding a rope running over a pulley to a 65kg sand bag find his speed which hits the ground??

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

accleration of system = a


a = g(m2-m1)/(m1+m2)


 a  =g(85-65)/(85+65)=4/3 m/s2


now using ,


                v2 = u2 +2as


initial velocity = 0


      v2 = 2*(4/3)*10                                     (s = 10m)


      v=5.16m/s

6 years ago
Fawz Naim
37 Points
										

Let the tension in the rope be T


using Newton's second law of motion


85g-T=85a ....1


T-65g=65a ....2


solve the two equations to get the value of 'a' 


now distance=10m


using third equation of motion


v^2=u^2+2aS


u=0


v^2=2aS


put the value of a and S to get velocity

6 years ago
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