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```
A person jumps onto a cement floor from a height of 1 m and comes to rest in 0.1 second .the same person on jumping from a height of 9 m into a sand pit, comes to rest in 1 second . Compare the forces exerted on him by cement floor and sand pit.```
6 years ago

Uttam Gulshan
31 Points
```										h=1 m.  h'=9 m.
t=0.1 s. t'=1 s.
Now force exerted in first case be F and in second case be F'.
Let the mass of man be m.
F=(m((2gh)^(1/2)))/t
F'=(m((2gh')^(1/2)))/t'
=> F/F'=((h/h')^(1/2))*(t'/t)
=>F/F'=10/3.
Hence , F'=(3/10)F.
```
6 years ago
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