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				   The time of flight of a projectile is 10 sec.its horizontal range is 100m.Calculate angle and velocity of projection

6 years ago


Answers : (2)


v2sin(2theta)=100g, vsin(theta)=5g,thus v2=25g2/sin2(theta), thus 50g2cot(theta)=100g, theta=arccot(1/5), v=10√26 m/sec

6 years ago

time of flight=2usin@/g=10........1

horizontal range=u^2sin2@ /g=100........2

 dividing 1by2

           usin2@/2sin@=10 or


  divide 1 by 3

            we get tan@=5 ,cos@=1/sqrt26

     on putting value of @ in 3 we get


6 years ago

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