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`        The time of flight of a projectile is 10 sec.its horizontal range is 100m.Calculate angle and velocity of projection`
7 years ago

Chetan Mandayam Nayakar
312 Points
```										v2sin(2theta)=100g, vsin(theta)=5g,thus v2=25g2/sin2(theta), thus 50g2cot(theta)=100g, theta=arccot(1/5), v=10√26 m/sec
```
7 years ago
510 Points
```										time of flight=2usin@/g=10........1
horizontal range=u^2sin2@ /g=100........2
dividing 1by2
usin2@/2sin@=10 or
ucos@=10....3
divide 1 by 3
we get tan@=5 ,cos@=1/sqrt26
on putting value of @ in 3 we get
u=10sqrt26
```
7 years ago
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