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ashok kumar Grade: 11
        The time of flight of a projectile is 10 sec.its horizontal range is 100m.Calculate angle and velocity of projection
6 years ago

Answers : (2)

Chetan Mandayam Nayakar
312 Points
										

v2sin(2theta)=100g, vsin(theta)=5g,thus v2=25g2/sin2(theta), thus 50g2cot(theta)=100g, theta=arccot(1/5), v=10√26 m/sec

6 years ago
vikas askiitian expert
510 Points
										

time of flight=2usin@/g=10........1


horizontal range=u^2sin2@ /g=100........2


 dividing 1by2


           usin2@/2sin@=10 or


           ucos@=10....3


  divide 1 by 3


            we get tan@=5 ,cos@=1/sqrt26


     on putting value of @ in 3 we get


    u=10sqrt26

6 years ago
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