Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        After a ball has been falling under gravity for 5 seconds it passes through a piece of glass and loses half  velocity. If it now reaches the ground in 1 seconds find the height of the glass above the ground. A particle is projected vertically upward from ground level with a speed of 50 m/s. For how long will it be more than 70 m above the ground?`
7 years ago

105 Points
```										Dear Shubham,
v = v0 + gt = 0 + (9.8m/s²)(5.0s) = 49m/s  After breaking through the glass, its speed has been reduced to roughly  half this: 25m/s. If it takes 1.0s to reach the ground with that speed,  then the height of the glass was:  Δy = v0t + 0.5gt² = (25m/s)(1.0s) + 0.5(9.8m/s²)(1.0s)² = 30m (rounded)
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Suryakanth –IITB
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
• Kinematics & Rotational Motion
• OFFERED PRICE: Rs. 636
• View Details
Get extra Rs. 51 off
USE CODE: Neerajwin