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Shubham Rathi Grade: 11
        

A balloon ascends with a uniform acceleration of 981 /8 cm/s2, at the end of half a minute a body is released from it, find the time that elapses before the body reaches the ground. [g = 9.81]

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

accelration of baloon is 981/8 cm/sec^2=9.8/8 m/sec^2


after half minute velocity of baloon is v=u+at


                                                       =9.8*30/8 m/sec                 (u=0)


total height attained by baloon is H=ut+at^2/2


                                                  =450*9.8/8 m


 at this time the particle is dropped so its velocity will be same as of baloon in upward direction....


     velocity of paticle is u=9.8*30/8 m/sec


    now using s=ut+at^2/2 for particle


       s=-H , u=9.8*30/8 ,g=-9.8,after putting these values we get a quadratic in t


2t^2 -15t-225=0


 t=15,-7.5 sec


 t=15 is required ans

7 years ago
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