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A ball is released from the top of a tower of height h meters. It takes T second to reach the ground. What is the position f the ball in T/3 second –
(A) h/9 meters from the ground
(B) 7h/9 meters from the ground
(C) 8h/9 meters from the ground
(D) 17/h18 meters from the ground
please explain
hey..according to ur question,it takes T time to travel a height H...therefore in T/3 sec it will travel a distance of h/9...using 2nd law of motion..i.e u=0,s=0+1/2gt^2...therefore its distance from ground will be H-H/9=8H/9....
D ANSWER WILL B C OPTION USIND 2ND LAW..
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