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nitin singh Grade: 12
        

I hope someone in here can help me out of this problem.
I know that for calculating the change in entropy of a system (LaTeX Code: \\Delta S ) we can use this formula :

LaTeX Code: \\Delta S =LaTeX Code: \\int δq/T
Well the problem is here, when we calculating ΔS for an adiabatic process we know Q= 0 so ΔS=0 in this process, but why we just can't let Q be equal to zero in a free expansion (while we know that in free expansion W=Q=0) and get to the same result (ΔS=0) for the free expansion process?

6 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear nitin,


The formula you wrote is only valid for a reversible process. And the free expansion is not a reversible process. To calculate the difference in entropy in this case, connect the initial and final state by any reversible path, for which generally you won't have dQ = dL = 0, and use your formula on this path.




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Sagar Singh


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sagarsingh24.iitd@gmail.com



6 years ago
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