Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Kinematics & Rotational Motion
  • View Details
Get extra R 600 off
USE CODE: chait6


sir, i am finding it very difficult to draw free body diagrams. pls help.

6 years ago


Answers : (1)


dear vivek,



Before you start to draw fre body diagram clearly state identify your System(The body to which you want to draw FBD).

And then remove everything other than system and draw the figure.

Now identify the active forces on the body(Gravitational force,Externally applied loads)

In Free body diagram along with active forces you've to show the reactions exerted ON the body BY the external elements.

Though many a times direction of reactive force is confusing so follow the above statement(on-by).Eventhough you give an opposite direction it doesnt effect your final answer.

You must've known about some basic reaction forces like hinge reactions and fixed joint reaction.

As per 12th standard i've explained an example below.



Now suupose u are drawing FBD of block having mass 'm' and also assume that if is moving down with accelaration 'a'.

then as I stated, first select your system(here sytem is block).

Now active forces--> Here, only external force is  gravitational force

Reactive forces: The surface in which block is lying will exert a normal reaction force'N'.As the block is sliding down  with an accelaration 'a' have the frictional force between block and suface will oppose its motion . Hence frictional force 'f' is shown.

The inertia force will also come into play . because of accelaration  of body and always it acts opposite directionto accelaration and having magnitude= m*a


If U want FBD for any particular question feel free to post.You can also refer to any good physics book like H C verma


thanks and regards,


6 years ago

Post Your Answer

Other Related Questions on General Physics

what is work energy thereom...................................?
The work-energy theorem is a generalized description of motion which states that work done by the sum of all forces acting on an object is equal to change in that object’s kinetic energy....
dolly bhatia one month ago
The work W done by the net force on a particle equals the change in the particle`s kinetic energy KE: W = Δ K E = 1 2 m v f 2 − 1 2 m v i 2 . The work-energy theorem can be derived from...
Sushmit Trivedi one month ago
For any net force acting on a particle moving along any curvilinear path, it can be demonstrated that its work equals the change in the kinetic energy of the particle by a simple derivation...
rahul kushwaha 3 months ago
The cieling of long hall is 25 m high What is the maximum horizontal distance that a ball thrown with a speed of 40 ms can go without hitting the ceiling of wall? Plz explain with a DIAGRAM
Let the angle of throwing be Q with respect to the ground So, the range is R = 40*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is half...
Tapas Khanda 5 months ago
Let the angle of throwing be Q with respect to the ground So, the range is R = 30*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is half...
Tapas Khanda 5 months ago
Diagram is not required to solve this question. You can directly use the formula to find range : R = (v^2/g)*sin2Q Maximum height reached, H = v^2*sin^2Q/2g So, 25 = 40^2*sin^2Q/(2*9.8) So,...
Tapas Khanda 5 months ago
What harmfull gases are produced when we burn plastics? And can we burn plastics?
I`m doing a project, can someone help me, How to reduce those toxic contents when plantic are burnt Like sulphur, nitrogen etc
2017 years ago
a packet is released from a balloon accelerating upward with acceleration a. the acceleration of packet just after the release is
Since the ballon was moving upward with acceleration a, there is a force of gravity on the packet too. The balloon is moving upward bexause the reaction force R>W, weight of the packet. As...
Shaswata Biswas 3 months ago
Just after the release the packet posses only the component of the velocity aquired. Here the accleration of the balloon has no effect on the acceration of the body. When the body is...
Shaswata Biswas 3 months ago
The accleration of the packet will be `g` acting downward as no external force other then gravity working on will achieve the case of free fall. If I am wrong please ..explain the...
Chandan kumar mandal 2 months ago
The potential energy of a particle of mass 1kg moving along x-axis is given by U(x)=[x^2/2-x]J. If total mechanical energy of the particle is 2J find its maximum speed.
total mechanical energy = U+ K.E to attain maximum speed the obect must have maximum K.E as K.E will be maximum , U has to be minimum (conservation of energy )given - U(x) = x²/2-xfor this...
fizaparveen 2 months ago
We know that the object accelerate till force is applied on it and it attains maximum velocity just after the force becomes zero... SO we know the negative of potential energy gradient is...
Suraj Singh 21 days ago
Ans- 2Speed will be max when kinetic energy is maximum so potential energy will be minimum so differentiating the function put it equal to 0 so we obtain minimum for x=0 now kin potential...
rishabh doshi 2 months ago
if a body move with u velocity then after collide with wall and remove with v velocity what is the impulse
Hi aman, I think this might help as we know that Impulse and also F=m(dv/dt) so (here m is the mass of body and dv/dt =acc) here p is the momentum ans delta p is change in momentum hence in...
Ankit Jaiswal 3 months ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 6,000 off
USE CODE: chait6

  • Kinematics & Rotational Motion
  • View Details

Get extra R 600 off
USE CODE: chait6

More Questions On General Physics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details