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Khushboo Singh Grade: 12
        

two particle A and B r initially located at same point in uniform gravitational field of earth . At a certain moment they r projected with speed v  and v  horizontally in opposite direction the saperation between them at that moment when their velocity vector become perpendicular to each other.

6 years ago

Answers : (2)

Puneet Mittal AskiitiansExpert-IITD
22 Points
										

Hi Khushboo,


The Answer to the above question is as follows :


Let A travels towards left and B travels towards right.


When their velocities are perpendicular with each other, Let angles of velocity vectors Va and Vb be α and β  with horizontal,


Thus tanα = Vay / Vax


Vay = 0 - g*t  Vax = v in left direction


tanα = 1/(v)*g*t   (considering only magnitudes)


And tanβ = Vby / Vbx


Vby = 0 - g*t  , Vbx = v in right direction


Thus tanβ = 1/(v)*g*t    (considering only magnitudes)


Thus tanα = tanβ


or  α = β


Also  α + β = 90 degree , ( As the velocites are perpendicular,  α + 90 + β  = 180 degree if you draw the diagram )


Thus  α = β = 45 degrees upon solving above eqns.


Speration between them at this point is Distance travelled by a in left hroizontal direction +  Distance travelled by b in right hroizontal direction


S = separation = Vax*t + Vbx*t = 2vt


tan45 degrees = 1 , Thus 1 = gt/v or t = v/g


Hence S = 2v*v/g = 2v2/g is the Answer


Please feel free to ask as many question you have.


Puneet

6 years ago
shashank mishra
14 Points
										

The answer is:


2v2/g

6 years ago
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