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`        two particle A and B r initially located at same point in uniform gravitational field of earth . At a certain moment they r projected with speed v  and v  horizontally in opposite direction the saperation between them at that moment when their velocity vector become perpendicular to each other.`
7 years ago

22 Points
```										Hi Khushboo,
The Answer to the above question is as follows :
Let A travels towards left and B travels towards right.
When their velocities are perpendicular with each other, Let angles of velocity vectors Va and Vb be α and β  with horizontal,
Thus tanα = Vay / Vax
Vay = 0 - g*t  Vax = v in left direction
tanα = 1/(v)*g*t   (considering only magnitudes)
And tanβ = Vby / Vbx
Vby = 0 - g*t  , Vbx = v in right direction
Thus tanβ = 1/(v)*g*t    (considering only magnitudes)
Thus tanα = tanβ
or  α = β
Also  α + β = 90 degree , ( As the velocites are perpendicular,  α + 90 + β  = 180 degree if you draw the diagram )
Thus  α = β = 45 degrees upon solving above eqns.
Speration between them at this point is Distance travelled by a in left hroizontal direction +  Distance travelled by b in right hroizontal direction
S = separation = Vax*t + Vbx*t = 2vt
tan45 degrees = 1 , Thus 1 = gt/v or t = v/g
Hence S = 2v*v/g = 2v2/g is the Answer
Puneet
```
7 years ago
shashank mishra
14 Points
```										The answer is:
2v2/g
```
7 years ago
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