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2 particles one with constant velocity of 50m/s and the other with uniform acceleration of 10m/s 2 start moving simultaneously from the same place in the same direction.They will be at a distance of 125 m from each other after?ans.5(1+root 2)s

2 particles one with constant velocity of 50m/s and the other with uniform acceleration of 10m/s2 start moving simultaneously from the same place in the same direction.They will be at a distance of 125 m from each other after?ans.5(1+root 2)s

Grade:12

1 Answers

Gokul Joshi AskiitiansExpert-IITK
42 Points
13 years ago

Dear Umme,

We can do it by relative motion concepts. From frame of 1st particle, u21 = -50 and a21 = 10.
s21 = 125 = u21 t + 1/2 a21 t2 = -50t + 1/2 10 t2
=> 25 = -10t + t2
Solving: t = 5 + 5 sqrt(2) = 5 (1 + sqrt(2)) seconds



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