MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
sree harshini Grade: 9
        

a body is throw upin a lift with a velocity 'u' relativeto the lift. it returns to the floor of lift in time t. then the upward acceleration to the lift is

6 years ago

Answers : (1)

Puneet Mittal AskiitiansExpert-IITD
22 Points
										

Hi Sree,


Let the upward accelaration of the lift is a' .


Now for an observer in the lift , a pseudo force ma' will be acting on the body ( of mass m ) in the direction opposite to the direction of motion of accelaration of lift.


Thus forces acting on body will be : ma' downwards and mg downwards.


Thus Net force = MA = ma' + mg where A is net accelaration of the body. A is  downwards.


Now, using equation of motion,


0 = ut + 1/2( - A )t2


1/2At2  = ut


At = 2u


A = 2u/t


Now a' + g = A


a' + g = 2u/t


Thus a' = 2u/t - g  is upward accelaration of the lift.


Please feel free to ask as many questions as you want.


Puneet

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 13,000 off
USE CODE: JEE1
  • Kinematics & Rotational Motion
  • OFFERED PRICE: R 600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details