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Neel Pratik Bhatt Grade: 9
        

A bullet of mass 10grms is travelling horizontally with a velocity of 150 m/sec strikes a stationary wooden block and comes to arest after 0.03 seconds. Calculate the distance of prnitration of the bullet into the wooden block.


please help!


 

7 years ago

Answers : (2)

Radhika Batra
247 Points
										

Dear neel,


Given that :


Initial velocity (u) = 150 m/s.


Final velocity (v)  =  0 m/s.


Time taken for the body to come at rest (t)= 0.03 sec.


Now according to newton's first law:


 v = u - at   -------------------------------------------  eq 1.


so from this equation value of :  a = (u/t).


Now from the euation we have :


s = ut - 1/2at2 ----------------------------------------- eq 2.


put the values of u, t, a in the 2nd equation.


after solving we will get that :


s = 4.5m.


Thus the bullet will  penetrate 4.5 meters inside the wodden block.


 


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thanks and regards.

7 years ago
sidharth G
18 Points
										

mass of bullet = 0.01 kg


initial vel ,u = 150 m/s


final vel , v= 0


time= 0.03s


distance = s


v=u+at


v2=u2+2as


use these eq to find a(accelaration) and s respectively .u will get the answer


 

7 years ago
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