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```        A bullet of mass 10grms is travelling horizontally with a velocity of 150 m/sec strikes a stationary wooden block and comes to arest after 0.03 seconds. Calculate the distance of prnitration of the bullet into the wooden block.
```
7 years ago

247 Points
```										Dear neel,
Given that :
Initial velocity (u) = 150 m/s.
Final velocity (v)  =  0 m/s.
Time taken for the body to come at rest (t)= 0.03 sec.
Now according to newton's first law:
v = u - at   -------------------------------------------  eq 1.
so from this equation value of :  a = (u/t).
Now from the euation we have :
s = ut - 1/2at2 ----------------------------------------- eq 2.
put the values of u, t, a in the 2nd equation.
after solving we will get that :
s = 4.5m.
Thus the bullet will  penetrate 4.5 meters inside the wodden block.

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7 years ago
sidharth G
18 Points
```										mass of bullet = 0.01 kg
initial vel ,u = 150 m/s
final vel , v= 0
time= 0.03s
distance = s
v=u+at
v2=u2+2as
use these eq to find a(accelaration) and s respectively .u will get the answer

```
7 years ago
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