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The question is attached as a picturePlease answer my question.

The question is attached as a picturePlease answer my question.

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Grade:12

1 Answers

Soumya Ranjan Mohanty
117 Points
6 years ago
Dear student,
[L]=[c]^a*[G]^b*[e^2/(4*pi*epsilon0)]^c
[L]=[LT^-1]^a [M^-1L^3T^-2]^b [ML^3 T^-2]^c
[L]=L^(a+3b+3c)*M^(-b+c)*T^(-a-2b-2c)
so equating, a+3b+3c=1
-b+c=0
a+2b+2c=0
solving these equations,
we get a=-2,b=-1/2 and c=1/2
so L = 1/c^2 *[G* e^2/(4*pi*epsilon0)]^1/2
So, (3) is the correct answer.
Thanks,
Soumya Ranjan Mohanty.
 

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