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The equation of circle passing through (1,-3)and points common to two circles x2+y2-6x+8y-16=0,x2+y2+4x-2y-8=0 is

The equation of circle passing through (1,-3)and points common to two circles x2+y2-6x+8y-16=0,x2+y2+4x-2y-8=0 is

Grade:11

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
7 years ago
Use family of circles to get any circle from points of these circles . And from the new circle find out centre and mark out its distance from 2 given points at whch the circle intersects .

You will get a quadratic an d hence the answer

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