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solve for x: log x+1 (x 2 + x - 6) 2 = 4 log 5 120 + (x - 3) – 2.log 5 (1 – 5 x-3 ) = -log 5 (0.2 – 5 x-4 )

 
solve for x:
  1. logx+1(x2 + x - 6)2 = 4
  2. log5120 + (x - 3) – 2.log5(1 – 5x-3) = -log5(0.2 – 5x-4)

Grade:12

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
9 years ago
For the part 1)
try to write “4” as 4*logx+1(x+1) and equate it to the left hand side

Apply various definition of existence of equation You will get the answer....


For part 2)

try to combine all the log terms in one package and then compare it with the the right hand side . You will get an equation in “x ” which will be easy to solve



Thanks

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