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Given the standard electrode potentials, K+/K = -2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V, Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V Arrange these metals in their increasing order of reducing power.?

Given the standard electrode potentials,
K+/K = -2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V,
Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.?

Grade:Upto college level

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
Here lower the value of reduction potential(with sign), more is the reducing power of metal. Hence, in all of these given, pottasium is of the most reducing character and Ag is the lowest reducing agent.
Now we can easily arrange these, according to the values.
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