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ACORDING TO NEW RULE 50% OF JEE AND 50%OF 12TH IS CONSIDER ,SO WE SHOULD TAKE ADMETION IN CBSE OR DOIIT CLASSES IN INSTITUTION AND TAKE ADMITION IN STATE BORD PLEASE GIVE ME SAGETION

ACORDING TO NEW RULE 50% OF JEE AND 50%OF 12TH IS CONSIDER ,SO WE SHOULD TAKE ADMETION IN CBSE OR DOIIT CLASSES IN INSTITUTION AND TAKE ADMITION IN STATE BORD PLEASE GIVE ME SAGETION 

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Amit Shekhar IIT Kharagpur
askIITians Faculty 25 Points
9 years ago
The JEE rank list or merit list is prepared on the basis of the candidates' class XII Board marks and the marks scored in JEE. The marks scored by a candidate in Class XII in State board or equivalent examination is provided 40 per cent wieghtage while the marks scored in JEE gets 60 per cent wightage.

Although, according to JEE notification, the weightage to school board/ equivalent examination marks will be brought into consideration only after normalisation. This means to say that there has to be a method to be able to compare marking systems of different boards.

The detailed procedure for normalization of Qualifying examination marks is as follows:

Note down the aggregate marks (A0) obtained by each student in JEE- Main.

Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main. The variable B0 is only a base for calculating percentile (P), which is further used to get corresponding JEE (Main) marks.

Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.

Also, determine theJEE- Mainaggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE-Main by the students of that board. Regard this as B2.

The normalized board score of the candidate was computed as:

Bfinal = 0.5 * (B1 + B2)

For the purpose of admission to CFTIs where it has been decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list was computed as:

C = 0.6 * AO + 0.4 * Bfinal

Five subjects to be used for normalization:

1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology, Biotechnology and Technical Vocational subject
4. One language
5. Any subject other than the above four subjects.

In respect of 3, 4 and 5, the best mark in a given category will be chosen.

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