A car starts from rest travelling with constant acceleration. if distance covered by it in 10 th second of its journey is 19m, what will be the acceleration of the car- 1)4m/s^2 2)3m/s^2 3)2m/s^2 4)1m/s^2

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Neeti · Answer

Formula for distance covered in n th second = S = u + a/2(2n-1) In this question, u=0. n = 10 , s= 19 . On applying values to the equation we get: 19 = a/2 (2x 10 -1 ) therefore a = 2m/s^2 Please approve the answer if you think it’s useful :)

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A car starts from rest travelling with constant acceleration. if distance covered by it in 10 th second of its journey is 19m, what will be the acceleration of the car- 1)4m/s^2 2)3m/s^2 3)2m/s^2 4)1m/s^2

A car starts from rest travelling with constant acceleration. if distance covered by it in 10^th second of its journey is 19m, what will be the acceleration of the car-

1)4m/s^2
2)3m/s^2
3)2m/s^2
4)1m/s^2

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A car starts from rest travelling with constant acceleration. if distance covered by it in 10 th second of its journey is 19m, what will be the acceleration of the car- 1)4m/s^2 2)3m/s^2 3)2m/s^2 4)1m/s^2

A car starts from rest travelling with constant acceleration. if distance covered by it in 10th second of its journey is 19m, what will be the acceleration of the car- 1)4m/s^22)3m/s^23)2m/s^24)1m/s^2

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A car starts from rest travelling with constant acceleration. if distance covered by it in 10^th second of its journey is 19m, what will be the acceleration of the car-

1)4m/s^2
2)3m/s^2
3)2m/s^2
4)1m/s^2