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```				   Tow numbers are selected randomly from the first fifteen natural numbers.If the sum of the numbers selected is even,find the probability that both numbers are even?
```

6 years ago

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```										Dear LINTA
sum of the selected number  will be even is both are enen or both are odd.
we  have   1,3,5,7,9,11,13,15   odd number
2,4,6,8,10,12,14     even number

2 even number can be selected = 7C2
2 odd number can be selected = 8C2

so probability = 7C2/(7C2  + 8C2 )
Please  feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we  will get you the answer and detailed  solution very  quickly.   We are all IITians and here to help you in your IIT JEE preparation.  All the best.   Regards, Askiitians Experts Badiuddin
```
6 years ago

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