Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Tow numbers are selected randomly from the first fifteen natural numbers.If the sum of the numbers selected is even,find the probability that both numbers are even? `
7 years ago

147 Points
```										Dear LINTA
sum of the selected number  will be even is both are enen or both are odd.
we  have   1,3,5,7,9,11,13,15   odd number
2,4,6,8,10,12,14     even number

2 even number can be selected = 7C2
2 odd number can be selected = 8C2

so probability = 7C2/(7C2  + 8C2 )
Please  feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we  will get you the answer and detailed  solution very  quickly.   We are all IITians and here to help you in your IIT JEE preparation.  All the best.   Regards, Askiitians Experts Badiuddin
```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Engineering Entrance Exams

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details