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Charges q and –q are at position vectors and respectively from an arbitrary origin. Moment of the charge q about chosen origin is and respectively. Now dipole moment of the system is equal to vector sum of moments of q and –q, which is given by . Now we can see that is pointing from –q to +q. Hence dipole moment is vec P is pointing from –q to +q.
Ooops... there is a small mistake in the diagram. The vector showing the moment of charge –q should point in opposite direction.
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