Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

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Khimraj · Answer

Just write the expression and then compareF= Kq(-q)/r²Now q` = 1/4qAnd -q`= -1/4qF` = k(q/4)(-q/4)/r²F` = F/16

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Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

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Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes

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