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This is a parallel plate capacitor in which a dielectric is introduced of dielectric constant k so what u have to find is 1) electric field in the gap between the parallel plate capacitor qnd dielectric slab 2) electric field in the dielectric slab widthness of dielectric is t

This is a parallel plate capacitor in which a dielectric is introduced of dielectric constant k so what u have to find is 1) electric field in the gap between the parallel plate capacitor qnd dielectric slab 2) electric field in the dielectric slab widthness of dielectric is t

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Grade:12

1 Answers

Umakant biswal
5349 Points
7 years ago
@ rohit 
your questions are not clear also the image , kindly upload a clear image without that uc browser tagup . 
thats blocking the question as well as its figure . 
but , as per my understanding , i am giving the correct approach toi this question . 
1- the space in between the plate will have the same electric field which was there before the dieletric. 
apply this concept to solve the frst bit of this question . 
for the 2nd bit 
consider the empty space of capacitor also a capacitor,apply series combination . 
you have two air capacitor and a dielectric capacitor.
apply series combi to to find net Capacitance . 
HOPE IT CLEARS YOUR QUERY 
IF NOT THEN POST A DIFFRENT QUESTION WITH CLEAR IMAGE 
ALL THE BEST .. 

 

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