In a uniform electric field the potential is 10 V at the origin and 8 V at points (1,0,0)m,(0,1,0)m and (0,0,1)m.The potential at point (1,1,1)m will be

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Vikas TU · Answer

From inetegearl, dV/dr = k (let) on integerating we get, V = V’ + k(xi + yj + zk)at origin, V = V’ = 10 volts. And substituing for all three points and solving we get k = -2. Hence, at (1,1,1) point, => 10 – 2*(1+1+1) => 4 volts.

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In a uniform electric field the potential is 10 V at the origin and 8 V at points (1,0,0)m,(0,1,0)m and (0,0,1)m.The potential at point (1,1,1)m will be

In a uniform electric field the potential is 10 V at the origin and 8 V at points (1,0,0)m,(0,1,0)m and (0,0,1)m.The potential at point (1,1,1)m will be

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In a uniform electric field the potential is 10 V at the origin and 8 V at points (1,0,0)m,(0,1,0)m and (0,0,1)m.The potential at point (1,1,1)m will be

In a uniform electric field the potential is 10 V at the origin and 8 V at points (1,0,0)m,(0,1,0)m and (0,0,1)m.The potential at point (1,1,1)m will be

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