2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed in oil of permittivity 5 to obtain the same force of interaction?

Question

aniket · Answer

first find out the force due to the charge in air then you know that ∂=5 you get r =0.089 use F= (1/4pi∂∂not) q1q2/r 2 where r is unknown

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2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed in oil of permittivity 5 to obtain the same force of interaction?

2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed in oil of permittivity 5 to obtain the same force of interaction?

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2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed in oil of permittivity 5 to obtain the same force of interaction?

2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed in oil of permittivity 5 to obtain the same force of interaction?

1 Answers

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