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`        Two identical balls are charged by rubbing against each other.They are suspended from a horizontal rod through two stringsof lenghts 20cm each the separation between the suspended points being 5cm.In equilibriumthe separation between the balls is 3cm.find the mass of each ball and tension in the string.the charge on each ball is 0.000000002C (WITH MAGNITUDE).`
7 years ago

28 Points
```										Dear Chinthalapudi Prashanth,
Ans Let the strings make an angle θ with the vertical
then Tcosθ=mg.............(1)
Tsinθ=K q²/r²...............(2)
Dividing 2 by 1 we get
tanθ=Kq²/mgr²
Solving we get,
m=8×10^-5 Kg. each
N.B: You can also solve it by using moment equations TRY IT.
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Chinthalapudi Prashant!!!

Regards,
```
7 years ago
ayush aggarwal
4 Points
```										answer posted by everyone is right but try to solve this problem using lamis theorem . it is the shortest and the best way to solve this
```
7 years ago
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