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a solid sphere of radius r is charged uniformly.at what distance from it surface electric potential is half of that of at its centre.
ans:r/3
Dear shefali
we know potential outside the sphere is V1 = kQ/x where x is the distance from the center x>r
and potential inside the sphere V1 = kQ/2r [3-x2/r2]
for center put x=0 Vo = 3kQ/2r
condition given is V1 = Vo/2
kQ/x = (3kQ/2r)/2
x=4r/3
distance from the surface is =x-r
= 4r/3 -r =r/3
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