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```				   a solid sphere of radius r is charged uniformly.at what distance from it surface electric potential is half of that of at its centre.
ans:r/3
```

6 years ago

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```										Dear shefali
we know potential outside the  sphere is V1 = kQ/x     where x is the distance from the center x>r
and  potential inside the sphere V1 = kQ/2r [3-x2/r2]
for  center put x=0  Vo = 3kQ/2r
condition given is V1 = Vo/2
kQ/x  = (3kQ/2r)/2
x=4r/3
distance from the surface is  =x-r
= 4r/3 -r =r/3
Please feel free to post as many doubts  on our discussion forum as you can. If you find any question Difficult to understand - post it here and we  will get you  the answer and detailed  solution very  quickly.   We are all IITians and here to help you in your IIT JEE preparation.  All the best.   Regards, Askiitians Experts Badiuddin
```
6 years ago

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