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pallavi pradeep bhardwaj Grade: 12
        

Three particles have charges 20 mc each and they are fixed at the corners of an eq. triangle of side 0.5m The force on each of the particle has magnitude

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi


force between two charge


F= 1/4∏ε (20 *10-6)2/(.5)2


  = 9*109  * 4*10-10 /.25


  =14.4 N


this force act along the side of triangle .


in one charge two force act along the direction of side and angel between then is 60


resultant force F'=[F2 +F2 +2FFcos60]1/2


                              =F√3


                     =24.94 N


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Badiuddin

7 years ago
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