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pallavi pradeep bhardwaj Grade: 12
`        A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be`
8 years ago

## Answers : (8)

Badiuddin askIITians.ismu Expert
147 Points
```										Dear pallavi
let parts are sepereted at a distance of d
so repulsion force F= k q(Q-q)/d2
here Q and d are constant so for maximum force differentiate the force w.r.t q
dF/dq = k/d2 [Q -2q]
for maximum force dF/dq=0
Q-2q=0
Q/q =2
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
All the best. Regards,Askiitians ExpertsBadiuddin
```
8 years ago
Karthik Pasupulatei
38 Points
```										i cant understand how todifrentiate f w.r.t q
```
2 years ago
Hermione Weasley
12 Points
```										F = kq(Q-q)/r^2=> F = k(Qq-q^2)/r^2Since Q, r, and k are all constants,Differentiating,dF/dq = d (k(Qq-q^2)/r^2) / dq=> dF/dq = k/r^2 * [Q – 2q]Since the maximum force is a constant, dF/dq must be equal to 0.Hence, k/r^2 * [Q – 2q] = 0=> Q – 2q = 0=> Q = 2q=> q = Q/2 or Q/q = 2
```
2 years ago
Abhi
21 Points
```										I have a doubt why df | da is done fgdswtyiplhxzssd hdgigc bhgdriov. My marks the correct the same problem for your email address for typos of you have received your mail to postmaster of u want it on a regular member and it will not work in progress of u vivek of my first thought it would have a look on your site at a very nice and warm weather was just
```
9 months ago
Ashish Kumar
36 Points
```										Let q and Q-q be the charges on the two objects. Then force between the two object is F =1/ 4 pi Eò . q(Q-q)/ r^2     where r is the distance between them....For F to be max ,  dF/dq = 0  Or 1/4pi E0 .r^2 .d(qQ-q^2)/ dq= 0 Q-2q =0 q = Q/2    answer....
```
8 months ago
Leena Surendran
26 Points
```										I dI`d not understand  the part where the maximum  force is a constant. And why did you equate dF/dq to zero?
```
7 months ago
Deepti
11 Points
```										We equate dF/dq=0 because it`s one of the rules of differentiation where we equate it to 0 when we want any maximum or minimum value of something
```
3 months ago
Shailendra Kumar Sharma
179 Points
```										q and (Q-q) be charges So the force (F) =Kq(Q-q)/r2To maximize dF/dq=0so (q-Q+q=0)q=Q/2in other words, two charge force will increase as the multiple will increase, but when the multiple will be maximum at the mid point only.
```
3 months ago
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