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pallavi pradeep bhardwaj Grade: 12

A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be

7 years ago

Answers : (4)

Badiuddin askIITians.ismu Expert
147 Points

Dear pallavi

 let parts are sepereted at a distance of d

so repulsion force F= k q(Q-q)/d2

     here Q and d are constant so for maximum force differentiate the force w.r.t q

 dF/dq = k/d2 [Q -2q]

 for maximum force dF/dq=0


                              Q/q =2

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7 years ago
Karthik Pasupulatei
38 Points
i cant understand how todifrentiate f w.r.t q
one year ago
Hermione Weasley
12 Points
F = kq(Q-q)/r^2
=> F = k(Qq-q^2)/r^2
Since Q, r, and k are all constants,
dF/dq = d (k(Qq-q^2)/r^2) / dq
=> dF/dq = k/r^2 * [Q – 2q]
Since the maximum force is a constant, dF/dq must be equal to 0.
Hence, k/r^2 * [Q – 2q] = 0
=> Q – 2q = 0
=> Q = 2q
=> q = Q/2 or Q/q = 2
one year ago
21 Points
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8 hours ago
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