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The excess of electron that must be placed on each of two small spheres spaced 3 cm apart if the force of repulsion between the spheres is to be 10^-19 N is

6 years ago


Answers : (1)


Dear pallavi

let the charge on spheres is q

so F= 1/4∏ε qq/.032

  given F= 10-19

       1/4∏ε qq/.032 =10-19

 9 *109 * q2 /.032 =10-19 


1 electron has  1.6 * 10-19 C  

 ne =q

 n=q/e =10-16/1.6 * 10-19 C


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