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Three charges 4q,Q and q are in straight line in the position o,l/2 and l respectively the resultant force on q will be  zero

7 years ago

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Dear pallavi


two force are acting on q ,one due to 4q and second due to Q


F1 = 1/4∏ε (4q)q/l


F2 = 1/4∏ε (Q)q/(l/2)


      = 1/4∏ε (4Q)q/l


 F1 +F2 =0


1/4∏ε (4q)q/l2   +  1/4∏ε (4Q)q/l=0


 Q=-q


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7 years ago

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